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Find the area under the graph of $y=\sin x$ between $x=0$ and $x=\pi$. 

Find the area under the graph of $y=\sin x$ between $x=0$ and $x=\pi$.

Calculus Integrals Trigonometric Functions
Emmadavis Emmadavis
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The area is

\[Area=\int_0^{\pi}\sin x dx = -\cos x|_0^{\pi}=-(\cos \pi - \cos 0)=-(-1-1)=2.\]

Nirenberg Nirenberg
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