A house costs 150,000 in 2002 and inflation rate has been 3% since 1990, what would the price of the house be in 1990
1 Answer
Let $P_0$ be the price of the house ain 1990. Then the price in 2012 (after 12 years) is
\[P_{12}=(1+\frac{3}{100})^{12}P_0=(\frac{103}{100})^{12}P_0.\]
Hence
\[P_0=(\frac{103}{100})^{-12}P_{12}=(\frac{103}{100})^{-12}150000=\$ 105,206.98.\]
Here we use the formula
\[P_n=(1+r)^n P_0,\]
where $r$ is the interest rate and $P_n$ is the price after $n$ years, and $P_0$ is the initial price.
574
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- 1 Answer
- 362 views
- Pro Bono
Related Questions
- ARIMA model output
- Compound Interest with monthly added capital
- What Are The Odds ?
- Find a number for 𝛼 so f(x) is a valid probability density function
- Operational Research probabilistic models
- Probability Question
- Probability
- Currently studying a grad level Statistical Inference course. I'd just like some clarification regarding how to obtain the Rao-Cramer Lower Bound for a statistic.