# Rewrite $\int_{\sqrt2}^{2\sqrt2} \int_{-\pi/2}^{-\pi/4} r^2cos(\theta)d\theta dr$ in cartesian coordinates (x,y)

Rewrite $\int_{\sqrt2}^{2\sqrt2} \int_{-\pi/2}^{-\pi/4} r^2cos(\theta)d\theta dr$ in cartesian coordinates (x,y).

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• I tried to evaluate your corrected answer on Wolfram, but it gives 0 as the answer. The original gives approx. 1.93. I'm afraid this isn't 100% correct.

• I doubled checked my computations. There was a mistake in the bounds for x. See the attached file.

• Great! Thank you.

• Let me know if you have any questions.

• Thanks for the tip!