Rewrite $\int_{\sqrt2}^{2\sqrt2} \int_{-\pi/2}^{-\pi/4} r^2cos(\theta)d\theta dr$ in cartesian coordinates (x,y)
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I tried to evaluate your corrected answer on Wolfram, but it gives 0 as the answer. The original gives approx. 1.93. I'm afraid this isn't 100% correct.
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I doubled checked my computations. There was a mistake in the bounds for x. See the attached file.
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Great! Thank you.
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Let me know if you have any questions.
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Thanks for the tip!
The answer is accepted.
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