Rewrite $\int_{\sqrt2}^{2\sqrt2} \int_{-\pi/2}^{-\pi/4} r^2cos(\theta)d\theta dr$ in cartesian coordinates (x,y)

Rewrite $\int_{\sqrt2}^{2\sqrt2} \int_{-\pi/2}^{-\pi/4} r^2cos(\theta)d\theta dr$ in cartesian coordinates (x,y).

Answer

Answers can be viewed only if
  1. The questioner was satisfied and accepted the answer, or
  2. The answer was disputed, but the judge evaluated it as 100% correct.
View the answer

3 Attachments

  • I tried to evaluate your corrected answer on Wolfram, but it gives 0 as the answer. The original gives approx. 1.93. I'm afraid this isn't 100% correct.

  • I doubled checked my computations. There was a mistake in the bounds for x. See the attached file.

  • Great! Thank you.

  • Let me know if you have any questions.

  • Thanks for the tip!

The answer is accepted.