Rewrite $\int_{\sqrt2}^{2\sqrt2} \int_{\pi/2}^{\pi/4} r^2cos(\theta)d\theta dr$ in cartesian coordinates (x,y)
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I tried to evaluate your corrected answer on Wolfram, but it gives 0 as the answer. The original gives approx. 1.93. I'm afraid this isn't 100% correct.

I doubled checked my computations. There was a mistake in the bounds for x. See the attached file.

Great! Thank you.

Let me know if you have any questions.

Thanks for the tip!
The answer is accepted.
 answered
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 $4.50
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