Early uni/college Calculus (one question)
Attatched question pic below. Answer doesn't have to be long, can be somewhat middle of short n long, but precise or straight to the point with the working. Thank you.
18
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
779
-
comment: upon reading the answer again I note that I made a miscalculation. In the third equation one should get f(\pi) * (1) - f(0) * (-1) instead of f(\pi) *(-1) - f(0)*(-1) - as cos(\pi)=-1 not 1. This should then enter into the second to last equation where you get 4 = f(0) + 9, the solution then becomes f(0)= 4-9 = -5.
-
Unfortunately it is not possible to edit answers once they are submitted, which is why I must put the correction in a comment instead.
-
Yes that is all good, thanks so much for your help!
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 795 views
- $3.00
Related Questions
- Proving f is continuous
- Compute $\lim_{x \rightarrow 0} \frac{1-\arctan (\sin(x)+1)}{e^{x}-1}$
- Need help with integrals (Urgent!)
- Compute $\lim\limits_{x \rightarrow 0} \frac{1-\frac{1}{2}x^2-\cos(\frac{x}{1-x^2})}{x^4}$
- Calculus Question
- Prove the trig identity $\sec x- \sin x \tan x =\frac{1}{\sec x}$
- Answer is done but need help
- Explain partial derivatives v2