Trigonometry sin cot CAST

5. (a) For the triangle, a=10, b=12, B=60°, labelled by convention, find all the angles and sides.

(b) Solve the following, 𝑠𝑖𝑛𝜗−𝑐𝑜𝑡^2𝜗=1, express your solution in degrees in the range –180°≤𝜗≤180°, and in radians in the range 0°≤𝜗≤2πrad. 

If someone could do these and show working out that would be great!

note from me (the cot is squared it just does not show the cot to the power of 2 very well)

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Erdos Erdos
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  • Sjh91 Sjh91
    0

    looks great. just regarding section b, is there further info required due to the angle range stated? if that makes sense.

  • Erdos Erdos
    0

    theta=90 degrees is the only solution to sin theta= 1 in the given range. So there is no further info required.

The answer is accepted.
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