Trigonometry sin cot CAST
5. (a) For the triangle, a=10, b=12, B=60°, labelled by convention, find all the angles and sides.
(b) Solve the following, 𝑠𝑖𝑛𝜗−𝑐𝑜𝑡^2𝜗=1, express your solution in degrees in the range –180°≤𝜗≤180°, and in radians in the range 0°≤𝜗≤2πrad.
If someone could do these and show working out that would be great!
note from me (the cot is squared it just does not show the cot to the power of 2 very well)
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