# Trigonometry sin cot CAST

(b) Solve the following, 𝑠𝑖𝑛𝜗−𝑐𝑜𝑡^2𝜗=1, express your solution in degrees in the range –180°≤𝜗≤180°, and in radians in the range 0°≤𝜗≤2πrad.

If someone could do these and show working out that would be great!

note from me (the cot is squared it just does not show the cot to the power of 2 very well)

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