# Verex form of a quadratic function

## 1 Answer

We will do this by factoring the coefficient of $x^2$ first and then completing the square:

\[f(x)=-4x^2+4x+3=-4(x^2-x-\frac{3}{4})\]

\[=-4(x^2-x+\frac{1}{4}-\frac{3}{4}-\frac{1}{4})\]

\[=-4(x^2-x+\frac{1}{4}-1)\]

\[=-4((x-\frac{1}{2})^2-1)\]

\[=-4(x-\frac{1}{2})^2+4,\]

which is in the vertex form.

Join Matchmaticians Affiliate Marketing
Program to earn up to 50% commission on every question your affiliated users ask or answer.

- 1 Answer
- 113 views
- Pro Bono

### Related Questions

- Algebra Word Problem #2
- When is Galois extension over intersection of subfields finite
- Donald is 6 years older than Sophia. In 4 years the sum of their ages will be 74. How old is Donald now?
- Algebra Word Problem 2
- Root of $x^2+1$ in field of positive characteristic
- Find $\lim _{x \rightarrow 0} x^{x}$
- Transformations of Parent Functions
- Fluid Mechanics - algebra