$Determine where the following function is discontinuous$

Question

$Determine where the following function is discontinuous$

Determine where the following function is discontinuous

$$f(x)=\frac{x^2-9}{3x^2+2x-8}.$$

Calculus Continuity Domain

User35

37

Report

Answer

The answer is accepted.

Join Matchmaticians Affiliate Marketing Program to earn up to a 50% commission on every question that your affiliated users ask or answer.

Answer 1

Answers can only be viewed under the following conditions:

The questioner was satisfied with and accepted the answer, or
The answer was evaluated as being 100% correct by the judge.

View the answer

The function $f$ is discontinuous when there is division by zero. Lets find the points where the denominator is zero
\[3x^2+2x-8=0 \Rightarrow x=\frac{-2\pm \sqrt{4-4\times 3 \times (-8)}}{2 \times 3}=\frac{-2\pm \sqrt{100}}{2 \times 3} \]
\[=\frac{-2\pm10}{6}=-2, \frac{8}{6}.\]
Thus the function $f$ is discontinuous at $x=-2$ and $x=\frac{4}{3}$.

Kateg

41

$Determine where the following function is discontinuous$

Answer

Related Questions

Search