How do you go about solving this question?
I've uploaded an image which contains the question.
The answers are $-\frac{5\pi }{24} ,-\frac{\pi }{24},\frac{19\pi }{24},\frac{23\pi }{24} $ But I don't know how you get $\frac{19\pi }{24},\frac{23\pi }{24} $ whenever I try and solve it I only get $-\frac{5\pi }{24} ,-\frac{\pi }{24}$.
87
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
3.7K
-
Where do we get the 2kπ from?
-
Cosine is periodic with period 2π. This means that cos(x) = cos( x + 2π ) = cos(x - 2π) = cos(x+4π) = cos(x-4π). So if x is a solution to cos(x) = sqrt(3)/2, x+2kπ will also be a solution,
-
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 868 views
- $5.00
Related Questions
- I really can't figure out equations with a power of 2 in it, please solve these and explain every step as if I was a baby.
- Prove that language L = {a^p ; p is prime} isn't regular using Myhill-Nerode theorem.
- The last six digits of the number $30001^{18} $
- Show that the $5\times 5$ matrix is not invertable
- Evaluate $\int_0^{\frac{\pi}{2}}\frac{\sqrt{\sin x}}{\sqrt{\sin x}+\sqrt{\cos x}} dx$
- Zariski Topology and Regular Functions on Algebraic Varieties in Affine Space
- Prove that $tan x +cot x=sec x csc x$
- Representation theory question