$stats - data analysis$

Question

$stats - data analysis$

check pic please

Statistics

Burgoos

226

Matchmaticians stats - data analysis File #1

File #1 (PNG)

Report

Answer

The answer is accepted.

Join Matchmaticians Affiliate Marketing Program to earn up to a 50% commission on every question that your affiliated users ask or answer.

Answer 1

Answers can only be viewed under the following conditions:

The questioner was satisfied with and accepted the answer, or
The answer was evaluated as being 100% correct by the judge.

View the answer

The model is:

$log\left(\frac{P(Y = 1)}{P(Y = 0)} \right ) = -6.38 - 2.73 * treatment + 0.14 * anxiety$

Which can be tranformed to:

$P(Y = 1) = \frac{e^{-6.38 - 2.73 * treatment + 0.14 * anxiety}}{1+e^{-6.38 - 2.73 * treatment + 0.14 * anxiety}} $

$= \frac{e^{-6.38 - 2.73 * 0 + 0.14 * 70}}{1+e^{-6.38 - 2.73 * 0 + 0.14 * 70}} $

$= \frac{e^{3.42}}{1+e^{3.42}} $

$= \frac{30.56942}{31.56942}$

$=0.9683238$

So the first answer is correct.

Schwartstack

277

$stats - data analysis$

Answer

Related Questions

Search