$stats - data analysis$

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$stats - data analysis$

check pic please

Statistics

Burgoos

226

Matchmaticians stats - data analysis File #1

File #1 (PNG)

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Answer 1

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The model is:

$log\left(\frac{P(Y = 1)}{P(Y = 0)} \right ) = -6.38 - 2.73 * treatment + 0.14 * anxiety$

Which can be tranformed to:

$P(Y = 1) = \frac{e^{-6.38 - 2.73 * treatment + 0.14 * anxiety}}{1+e^{-6.38 - 2.73 * treatment + 0.14 * anxiety}} $

$= \frac{e^{-6.38 - 2.73 * 0 + 0.14 * 70}}{1+e^{-6.38 - 2.73 * 0 + 0.14 * 70}} $

$= \frac{e^{3.42}}{1+e^{3.42}} $

$= \frac{30.56942}{31.56942}$

$=0.9683238$

So the first answer is correct.

Schwartstack

269

$stats - data analysis$

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