simultaneous linear inequalities (i don't have money, im only in 7th grade, im sorry)
1 Answer
From the first equation we get
\[2x - 6 + m < 0 \Rightarrow 2x<6-m \Rightarrow x< \frac{6-m}{2}.\]
From the second equation we get
\[4x - m > 0 \Rightarrow 4x>m \Rightarrow x> \frac{m}{4}.\]
Putting these two together, we get
\[ \frac{m}{4} <x< \frac{6-m}{2} \text{or} x\in (\frac{m}{4}, \frac{6-m}{2}). \]
Erdos
4.8K
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- 1 Answer
- 307 views
- Pro Bono
Related Questions
- How do you go about solving this question?
- Linear Algebra Assistance: Linear Combinations of Vectors
- Motorcycle Valve Clearance Calculation and Spacer Size Word Problem
- Find $\lim _{x \rightarrow 0} x^{x}$
- How do you do absolute value equations with inequalities?
- [Rotations in R^3 ] Consider R∶ R^3 → R^3 the linear transformation that rotates π/3 around the z-axis
- Prove that language L = {a^p ; p is prime} isn't regular using Myhill-Nerode theorem.
- Linear Algebra - Matrices and Inverses Matrices
