Find all functions $f: \mathbb{Z} \rightarrow \mathbb{Z}$ such that $f(2n)+2f(2m)=f(f(n+m))$, $\forall m,n\in \mathbb{Z}$
Answer
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 1685 views
- $15.00
Related Questions
- Show that the distance between two nonparallel lines is given by $\frac{|(p_2-p_1)\cdot (a_1\times a_2)|}{|| a_2\times a_1||}$
- Second order directional derivative
- Compute $\lim\limits_{x \rightarrow 0} \frac{1-\frac{1}{2}x^2-\cos(\frac{x}{1-x^2})}{x^4}$
- Derivative of FUNCTION
- Let $f:U\subset\mathbb{R} ^3\rightarrow \mathbb{R} ^2$ given by $f(x,y,z)=(sin(x+z)+log(yz^2) ; e^{x+z} +yz)$ where $U = { (x, y, z) ∈ R^3| y, z > 0 }.$ Questions Inside.
- Improper integral convergence
- Evaluate $\int \frac{x^5}{\sqrt{x^2+2}}dx$
- Find $\int\frac{dx}{2x^2-2x+1}$
There is a typo: f(2n)+2f(m)=f(f(n+m))
just for clarification you're saying that the typo, that is the *incorrect* relation is: f(2n)+2f(2m)=f(f(n+m)), and that the CORRECT relation is: f(2n)+2f(m)=f(f(n+m))?
Yes