Finding Binormal vector from the derivative of the Normal and Tangent.
Knowing that C is a regular, smooth curve parameterized by arc length.
It's $T'(0) = \frac{-1}{\sqrt10}(1,-1,0)$ and it's $N'(0) = \frac{-1}{\sqrt5}(0,0,-1)$ find the formula for $B(t)$ for all t. I have absolutely no idea what to do, I know that doing the cross product of $T'(0)$ with $N'(0)$ should give me $B'(0)$ but how do I go from there to $B(t)$?
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 790 views
- $4.00
Related Questions
- Multivariable Calc: Vector equations, parametric equations, points of intersection
- Multivariate Calculus Problem
- How to calculate a 3-dimensional Riemann integral
- Optimization Quick Problem
- Find the extrema of $f(x,y)=x$ subject to the constraint $x^2+2y^2=2$
- Let $ X = x i+ y j+z k$, and $r=||X||$. Prove that $\nabla (\frac{1}{r})=-\frac{X}{r^3}.$
- Use Stokes’ Theorem to calculate $\iint_{S} \nabla \times V· dS$ on the given paraboloid
- Find the coordinates of the point $(1,1,1)$ in Spherical coordinates
The bounty is a bit low.