Secondary 2 Maths
1 Answer
We have
\[500=(5x-5y)^2=(5x)^2+(5y)^2 -2\cdot (5 x)(5y)=25x^2+25y^2-50xy.\]
Since $xy=5$,
\[500=25x^2+25y^2-50xy=25x^2+25y^2-50\cdot 5=25x^2+25y^2-250\]
\[\Rightarrow 500+250=25x^2+25y^2\]
\[\Rightarrow 750=25(x^2+y^2)\]
\[\Rightarrow x^2+y^2=\frac{750}{25}=30.\]
Savionf
574
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- 1 Answer
- 446 views
- Pro Bono
Related Questions
- Element satisfying cubic equation in degree $5$ extension
- College Algebra Help
- Is the $\mathbb{C}$-algebra $Fun(X,\mathbb{C})$ semi-simple?
- How do you go about solving this question?
- Linear Algebra - Matrices (Multiple Choice Question) (1st Year College)
- Can enough pizza dough be made to cover the surface of the earth?
- Derive and show
- Evaluate $\int \ln(\sqrt{x+1}+\sqrt{x}) dx$
