Evaluate the limit Please explain all steps

We have
\[\lim_{h \rightarrow 0} \frac{\frac{4}{2+h}-2}{h}=\lim_{h \rightarrow 0} \frac{\frac{4-2(2+h)}{2+h}}{h}\]
\[=\lim_{h \rightarrow 0} \frac{\frac{4-4-2h}{2+h}}{h}=\lim_{h \rightarrow 0} \frac{\frac{-2h}{2+h}}{h}\]
\[=\lim_{h \rightarrow 0} \frac{-2h}{(2+h)h}=\lim_{h \rightarrow 0} \frac{-2}{(2+h)}\]
\[=\frac{-2}{2}=-1.\]