Find the extrema of $f(x,y)=x$ subject to the constraint $x^2+2y^2=2$

Find the extrema of $f(x,y)=x$ subject to the constraint $x^2+2y^2=2$. 

We should use the Lagrange multipliers method. 

Answer

Answers can be viewed only if
  1. The questioner was satisfied and accepted the answer, or
  2. The answer was disputed, but the judge evaluated it as 100% correct.
View the answer
The answer is accepted.