Analyzing the Domain and Range of the Function $f(x) = \frac{1}{1 - \sin x}$
What is the domain and range of the function $f$ defined by $f(x)=\frac{1}{1-\sin x}$?
In my book the solution is the following:![]()
But I have some questions:
1. The domain if $f$ is $\mathbb{R}$-$D$. The elements of $\mathbb{R}$ are real numbers, but the elements of the set $D$ are angles in radians. How is possible the domain is difference of two different sets? (If we want to find the largest domain, we can consider;for example, the set $A$ (whose elements are all the angles in radians) instead of $\mathbb{R}$, this makes more sense!).
2. For its range, I know it is using the following fact: $-1\leq \sin x\leq1$ $\forall x\in \mathbb{R}$. The above I know is true when $x$ is radians or degree. But how is possible that is right for real number? Actually, my question is the following: How to define senx and cosx for x real number in such a way that they continue to fulfill the known properties when x is radian o degree?
- accepted
- 1493 views
- $20.00
Related Questions
- Explain partial derivatives v3
- Calculating P values from data.
- Find the absolute extrema of $f(x,y) = x^2 - xy + y^2$ on $|x| + |y| \leq 1$.
- Somewhat simple trig question
- Find $n$ such that $\lim _{x \rightarrow \infty} \frac{1}{x} \ln (\frac{e^{x}+e^{2x}+\dots e^{nx}}{n})=9$
- What kind of online calculator I need to determine C on this problem?
- How do we define this choice function using mathematical notation?
- How do you go about solving this question?