Statistics and Probability
Check attachment for the questions. Please show work so I can understand 🙏
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
Blue
184
-
The 1st one is very clear. Thank you. What formula was used for the 2nd one? That's the ine I had the most trouble with. Thanks again!
-
And the probability seems wrong as well. Is it not 0.00039? Just trying to understand.
-
The formula for the amount of ways choosing n objects from a set of k objects is nCk (read "n choose k") = n!/((n-k)! * k!). Also, 0.00039 = 0.039%
-
Ok thank you so much for the help!
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 1841 views
- $10.00
Related Questions
- Probability of having a disease given a series of test results
- ANCOVA: R Squared and Partial Eta Squared
- Joint PDF evaluated over a curve $P_{U,V}$
- Explain how to get the vertical values when $n = 10$, $p = .5$, $\mu = 5$ and $\sigma^2 = 2.5$
- Five married couples are seated around a table at random. Let $X$ be the number of wives who sit next to their husbands. What is the expectation of $X$ $(E[X])$?
- Probability and Statistics Question
- X is number of (fair) coin flips needed to land m heads OR m tails. m is arbitrary natural number. Delfine CDF of X. (in It's simplest form)
- foundations in probability
