Statistics and Probability
Check attachment for the questions. Please show work so I can understand 🙏
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
184
-
The 1st one is very clear. Thank you. What formula was used for the 2nd one? That's the ine I had the most trouble with. Thanks again!
-
And the probability seems wrong as well. Is it not 0.00039? Just trying to understand.
-
The formula for the amount of ways choosing n objects from a set of k objects is nCk (read "n choose k") = n!/((n-k)! * k!). Also, 0.00039 = 0.039%
-
Ok thank you so much for the help!
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 969 views
- $10.00
Related Questions
- One Way Anova
- Use first set of data to derive a second set
- Algebra Word Problem 1
- foundations in probability
- Need help with negative proportions in experiment
- I need help with this Trig formula
- What would be the probability of "breaking the bank" in this 1985 Blackjack game? (Details in body)
- Webull problem