Statistics and Probability
Check attachment for the questions. Please show work so I can understand 🙏
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
Blue
184
-
The 1st one is very clear. Thank you. What formula was used for the 2nd one? That's the ine I had the most trouble with. Thanks again!
-
And the probability seems wrong as well. Is it not 0.00039? Just trying to understand.
-
The formula for the amount of ways choosing n objects from a set of k objects is nCk (read "n choose k") = n!/((n-k)! * k!). Also, 0.00039 = 0.039%
-
Ok thank you so much for the help!
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 1818 views
- $10.00
Related Questions
- Drawing a random number with chance of redrawing a second time. Best strategy that will never lose long term?
- Combinations of factors not observed, non-full rank design matrix. How to explain to investigator?
- Five times the larger of two consecutive odd integers is equal to one more than eight times the smaller. Find the integers.
- Pdf/cdf Probability
- CLT and probability
- Prove that the following sequences monotnically decrease and increase correspondingly. Since they are bounded, find the limit.
- Find the odds of event b
- How to calculate how much profit a loan of a certain risk level (based on dice rolls) is likely to make?
