Higher-dimensional spaces curiosity
1 Answer
I guess by intersection of 3D space in $R^4$ you mean intersection of two ahyperplanes:
\[a_1x+b_1y+c_1z+d_1w=e_1 \text{and} a_2x+b_2y+c_2z+d_2w=e_2.\]
It is possible for these two hyperplanes to have (I) no intersection or (II) coincide. However, if cases (I) and (II) does not happen, then using basic facts from linear algebra (you may wire $w$ in terms of the other three variables in one equation and replace in the other) one can conclude that the intersection will be a two-dimensional plane.
You conjecture is true in any dimension $n$, and can be proved with a very similar argument.
Poincare
133
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- 1 Answer
- 250 views
- Pro Bono
Related Questions
- Help Calculating Surface Area of a Cylinder with a Slit
- Land area calculation/verification
- Find the area of the shaded region
- Get area of rotated polygon knowing all coordinates and angle.
- Thickness of Multiple Spherical Shells
- Find the Curvature of Parabolic Wave
- Similar shapes
- Geometry Problem about Hole Placement on PVC Pipe