$How to find specific heat of a turpentine question?$

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$How to find specific heat of a turpentine question?$

A copper cylinder has a mass of 76.8 g and a specific heat of 0.092 cal/g ⁰C. It is heated to 86.5⁰ C and then put in 68.7 g of turpentine whose temperature is 19.5 ⁰ C. The final temperature of the mixture is 31.9⁰ C. What is the specific heat of the turpentine? Use the formula Q1=Q2 -> mATc =mATc. Provide correct units and show work.

Algebra

Jimmycallens

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Erdos

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Could you comment the formula? There seems to be a missprint.
Jimmycallens

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Q1=Q2 -> mATc= mATc. The A is like a triangle but I can't produce the triangle on my phone
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Erdos

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Could you comment the formula? There seems to be a missprint.
Jimmycallens

0

Q1=Q2 -> mATc= mATc. The A is like a triangle but I can't produce the triangle on my phone

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Using the fomrula
\[m_1 (T_{f}-T_{in}) C_1=-m_2 (T'_{f}-T'_{in})C_2,\]
Here $T_f, T'_f$ represents the final tempreture and $T_{in}, T'_{in}$ represents the initial tempreture of the two materials, $C_1, C_2$ are the specific heat constants. Substitunig the given information we have
\[76.8 (31.9-86.5) \times 0.092=- 68.7 (31.9-19.5)C_2\]
\[\Rightarrow -385.78176=-851.88C_2\]
\[\Rightarrow C_2 \frac{-385.78176}{-851.88}=0.452859 .\]
So the specific heat of the turpentine is 0.452859 cal/g ⁰C.

Erdos

Erdos

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I meant C_2= ... in the last equation.
Erdos

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$How to find specific heat of a turpentine question?$

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