Points of intersection between a vertical and horizontal parabola
This should be an easy one. I don't know why I can't figure it out. I can graph it and see the answer. I can even see that one point of intersection is (0,0). But I just can't figure out how to calculate the other points; (1/8,1/16) The answer is in the back of the book, there's just no explanation.
Please, show me how to get there.
The parabolas are
y = 4x^2 and x = 32y^2
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
Mathe
3.5K
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 440 views
- $5.00
Related Questions
- College Algebra Help
- Does $\lim_{n \rightarrow \infty} \frac{2^{n^2}}{n!}$ exist?
- I really can't figure out equations with a power of 2 in it, please solve these and explain every step as if I was a baby.
- Is the infinite series $\sum_{n=1}^{\infty}\frac{1}{n \ln n}$ convergent or divergent?
- True or false
- Determine the Closed Form of a Recurrance Relation
- Help needed finding a formula
- How does the change in $b$ in the quadratic formula $ax^2+bx+c$ move the parabola in an inverted version of the quadratic function?