Points of intersection between a vertical and horizontal parabola
This should be an easy one. I don't know why I can't figure it out. I can graph it and see the answer. I can even see that one point of intersection is (0,0). But I just can't figure out how to calculate the other points; (1/8,1/16) The answer is in the back of the book, there's just no explanation.
Please, show me how to get there.
The parabolas are
y = 4x^2 and x = 32y^2
Please, show me how to get there.
The parabolas are
y = 4x^2 and x = 32y^2
Answer
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Mathe
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The answer is accepted.
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