Order Notation 

Hello, could you guys tell me if i did this correctly based on the question since I am confused whether best run time means it grows the slowest or not?

Q) Rank the functions in Table 2 from best to worst runtime. Specifically, you should rank f (n) before g(n) if, and only if, f (n) = o(g(n)). There may be some ties (functions that grow at the same rate); you should indicates this with ”=”.


Best to Worst

(j) = (h)

(a)

(k) = (i) = (f) = (c)

(e) = (d)

(L)

(b)

Q) Rank in increasing order of growth rate

The second line is my solution

Discrete Mathematics
Sellymatt Sellymatt
15
Report

Answer

Answers can only be viewed under the following conditions:
  1. The questioner was satisfied with and accepted the answer, or
  2. The answer was evaluated as being 100% correct by the judge.
View the answer
Erdos Erdos
4.7K
  • Sellymatt Sellymatt
    0

    There is two parts one question at the bottom too! and Is this in best to worst run time? meaning (j) and (h) are the best run time and (a) is the worst run time? Also I am a bit confused about the constant, doesn't a constant have a slower run time than suppose a log function and therefore has a better run time

    • Erdos Erdos
      0

      Yes, it is best to worst run time (smallest run time to the largest run time). About the constant function, note that log (n) goes to infinity as n gets large which is much larges than a constant. So a constant run time is better than any log (n).

  • Erdos Erdos
    0

    I will add my solution to the second part in a few minutes.

    • Sellymatt Sellymatt
      0

      Thank you, I appreciate your help!

    • Erdos Erdos
      0

      You're most welcome :)

  • Sellymatt Sellymatt
    +1

    Oh okay I understand now! Thank you. I think you may have missed the other part that is below

The answer is accepted.
Join Matchmaticians Affiliate Marketing Program to earn up to a 50% commission on every question that your affiliated users ask or answer.