Prove that a closed subset of a compact set is compact.
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
1 Attachment
Erdos
4.8K
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 825 views
- $15.00
Related Questions
- Show that ${(x,\sin(1/x)) : x∈(0,1]} ∪ {(0,y) : y ∈ [-1,1]}$ is closed in $\mathbb{R^2}$ using sequences
- Suppose that $T \in L(V,W)$. Prove that if Img$(T)$ is dense in $W$ then $T^*$ is one-to-one.
- Existence of a Divergent Subsequence to Infinity in Unbounded Sequences
- Advanced Modeling Scenario
- real analysis
- Interior of union of two sets with empty interior
- separability and completeness
- real analysis
