Prove that a closed subset of a compact set is compact.
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
1 Attachment
Erdos
4.8K
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 821 views
- $15.00
Related Questions
- real analysis
- Prove that $\frac{d \lambda}{d \mu} = \frac{d \lambda}{d \nu} \frac{d \nu}{d \mu}$ for $\sigma$-finite measures $\mu,\nu, \lambda$.
- A Real Analysis question on convergence of functions
- Prove that convergence of the infinite series of integral of absolue values of a sequence of functions implies convergence
- Real Analysis
- Related to Real Analysis
- Show that there is either an increasing sequence or a decreasing sequence of points $x_n$ in A with $lim_{n\rightarrow \infty} x_n=a$.
- What is the Lebesgue density of $A$ and $B$ which answers a previous question?
