Vector-valued functions and Jacobian matrix
Since multivariable vector-valued functions are not covered in Stewart's Calculus I would like to clarify if I understand them correctly. So multivariable vector-valued function looks like this, right? $$f(x,y) = v<f1(x,y),f2(x,y)>$$
And Jacobian matrix would look like:
$$\begin{bmatrix} f1_x(x,y) & f1_y(x,y) \\ f2_x(x,y) & f2_y(x,y) \end{bmatrix} $$
Right?

106
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
2.1K
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 679 views
- $5.00
Related Questions
- In what direction the function $f(x,y)=e^{x-y}+\sin (x+y^2)$ grows fastest at point $(0,0)$?
- True-False real analysis questions
- Find the area bounded by the graphs of two functions
- Obtaining the absolute velocity of a moving train based on angle of raindrops with respect to vertical axis
- Variation of Parameter for Variable Coefficient Equation
- How do you prove integration gives the area under a curve?
- Use Stokes's Theorem to evaluate $\iint_S ( ∇ × F ) ⋅ d S$ on the given surface
- Rewrite $\int_{\sqrt2}^{2\sqrt2} \int_{-\pi/2}^{-\pi/4} r^2cos(\theta)d\theta dr$ in cartesian coordinates (x,y)