Differentiate $f(x)=\int_{\sqrt{x}}^{\arcsin x} \ln\theta d \theta$
Answer
You need to use the Leibniz rule:
\[(\int_{g(x)}^{h(x)}f(\theta)d\theta)'=h'(x)f(h(x))-g'(x)f(g(x)).\]
Using this formula we get
\[f'(x)=(\arcsin x)' \ln(\arcsin x)-(x^{1/2})'\ln(x^{1/2})\]
\[=\frac{1}{\sqrt{1-x^2}} \ln(\arcsin x)-\frac{1}{2}x^{-1/2}\ln (x^{1/2}).\]
4.8K
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 2748 views
- $2.00
Related Questions
- Algebra question
- Fields and Galois theory
- Evluate $\int_{|z|=3}\frac{1}{z^5(z^2+z+1)}\ dz$
- How to filter data with the appearance of a Sine wave to 'flattern' the peaks
- Find the amount of work needed to pump water out of full spherical tank
- Applied calc question 2 and 3
- Find the derivative of the function $f(x)=\sqrt{\sin^2x+e^x+1}$
- Calculus - stationary points, Taylor's series, double integrals..