Differentiate $f(x)=\int_{\sqrt{x}}^{\arcsin x} \ln\theta d \theta$
Answer
You need to use the Leibniz rule:
\[(\int_{g(x)}^{h(x)}f(\theta)d\theta)'=h'(x)f(h(x))-g'(x)f(g(x)).\]
Using this formula we get
\[f'(x)=(\arcsin x)' \ln(\arcsin x)-(x^{1/2})'\ln(x^{1/2})\]
\[=\frac{1}{\sqrt{1-x^2}} \ln(\arcsin x)-\frac{1}{2}x^{-1/2}\ln (x^{1/2}).\]
Erdos
4.7K
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 1683 views
- $2.00
Related Questions
- Evaluate$\int \sqrt{\tan x}dx$
- Find limit
- Use first set of data to derive a second set
- Prove the trig equation
- Find the area of the shaded region
- Profit maximizing with cost and price functions
- Given $|f(x) - f(y)| \leq M|x-y|^2$ , prove that f is constant.
- Derivative of $\int_{\sin x}^{x^2} \cos (t)dt$