$\lim_{x \rightarrow 0}\frac{1}{x^2 \log x}$
1 Answer
We can use L'hopital's rule
\[\lim_{x \rightarrow 0}\frac{1}{x^2 \log x} =\lim_{x \rightarrow 0} \frac{1}{\frac{\log x}{\frac{1}{x^2}}}=\frac{1}{\lim_{x \rightarrow 0} \frac{\frac{1}{x}}{\frac{-2}{x^3}}}=\frac{1}{\lim_{x \rightarrow 0} -\frac{1}{2}x^2}=-\infty.\]
Erdos
4.8K
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- 1 Answer
- 351 views
- Pro Bono
Related Questions
- Integrate $\int x^2(1-x^2)^{-\frac{3}{2}}dx$
- How do you prove integration gives the area under a curve?
- Prove that $\int_0^1 \left| \frac{f''(x)}{f(x)} \right| dx \geq 4$, under the given conditions on $f(x)$
- Evaluate $I(a) = \int_{0}^{\infty}\frac{e^{-ax^2}-e^{-x^2}}{x}dx $
- Epsilon delta 2
- Need help with finding equation of the plane containing the line and point. Given the symmetric equation.
- Use Green’s theorem to compute $\int_C x^2 ydx − xy^2 dy$ where $C$ is the circle $x^2 + y ^2 = 4$ oriented counter-clockwise.
- Studying the graph of this function
