Need help with finding equation of the plane containing the line and point. Given the symmetric equation.
A line $\vec{L}$ has symmetric equations $\frac{5}{3}x-3 = \frac{4}{3}y + 1 = \frac{1}{3}z + 2$.The point P (0,-1,-2) does not lie on the line. Find the equation of the plane which contains both the line $\vec{L}$ and the point P .
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This took me me about 20 minutes to answer. Please consider offering slightly higher bounties for your future posts.
The answer is accepted.
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