Need this for a presentation please help
ABCDE is inscribed in a circle with AB=BC=CD=DE=4 and AE=1. Compute
(1-cosB)(1-cosACE)
1 Answer
As suggested by Kav10, you need to use Cosine law for triangles ABC and ACE, and that that AC=CE.
Using Cosine law on the trianles ABC we have
\[AC^2=AB^2+BC^2-2AB \cdot BC \cos B=4^2+4^2-2\cdot 4\cdot 4 \cos B.\]
Hence
\[AC^2=32(1-\cos B). (1)\]
Using Cosine law on the trianles ACE we have
\[AE^2=AC^2+CE^2-2AC \cdot CE\cos (ACE),\]
since $AC=CE$ we get
\[1^2=AC^2+AC^2-2AC^2 \cos (ACE)=2AC^2(1-\cos (ACE)),\]
or
\[\frac{1}{2AC^2}=(1-\cos (ACE)). (2)\]
Multiplying (1) and (2) we get
\[\frac{1}{2}=32(1-\cos B)(1-\cos (ACE)).\]
Hence
\[(1-\cos B)(1-\cos (ACE))=\frac{1}{64}\]
Erdos
4.8K
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- 1 Answer
- 347 views
- Pro Bono
Related Questions
- Need formula help
- Pulley System
- Evaluate $\int_0^{\frac{\pi}{2}}\frac{\sqrt{\sin x}}{\sqrt{\sin x}+\sqrt{\cos x}} dx$
- Why if $\frac{opp}{adj} =x$, then $x \times hyp =$ The length of a line perpendicular to the hypotenuse with the same height.
- How do I negate the effect that the rotation of a plane has on a rectangle?
- Direction of forces acting on points A, B and C
- Determine the angle
- Find the composition function $fog(x)$
Use the Cosine Theorem for triangles ABC and ACE. Note that AC=CE. If you want full solution, it deserves a bounty.