What am I doing wrong?
$x^2-5x+6$ and $x^3-6x^2+11x+a$ have a common factor. Find the possible value of a.
The way I tried to solve it was.
$f(x)=x^3-6x^2+11x+a$
$x^2-5x+6=(x-2)(x-3)$ so then $x=3$ or $x=2$
$f(3)=3^3-6\times 3^2+11\times3 +a=6+a=0 $
$-6 $ $-6 $
$=a=-6$
$f(2)=2^3-6\times 2^2+11\times2 +a=6+a=0$
$-6 $ $-6 $
$=a=-6$
So a = -6 but in my textbook, it says that it is incorrect and the actual answer is -66 or 18
The way I tried to solve it was.
$f(x)=x^3-6x^2+11x+a$
$x^2-5x+6=(x-2)(x-3)$ so then $x=3$ or $x=2$
$f(3)=3^3-6\times 3^2+11\times3 +a=6+a=0 $
$-6 $ $-6 $
$=a=-6$
$f(2)=2^3-6\times 2^2+11\times2 +a=6+a=0$
$-6 $ $-6 $
$=a=-6$
So a = -6 but in my textbook, it says that it is incorrect and the actual answer is -66 or 18
32
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
3 Attachments
2.1K
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 2530 views
- $5.00
Related Questions
- Algorithm for printing @ symbols
- Five times the larger of two consecutive odd integers is equal to one more than eight times the smaller. Find the integers.
- Fields and Galois theory
- Linearly independent vector subsets.
- Sinusodial graph help (electrical)
- Find $x$ so that $\begin{pmatrix} 1 & 0 & c \\ 0 & a & -b \\ -\frac{1}{a} & x & x^2 \end{pmatrix}$ is invertible
- Induced and restricted representation
- Get area of rotated polygon knowing all coordinates and angle.