Existence of golobal minimum point for continuous functions on $\mathbb{R}^2$
Let
1. $g:[0,\infty)\rightarrow \mathbb{R}$ such that $\lim_{t\rightarrow \infty}g(t)=\infty$
2. $f: \mathbb{R}^2\rightarrow \mathbb{R}$ continues such that for all (x,y): f(x,y) $\geq$ g($\sqrt{x^2+y^2} $ ).
Prove that f has a global minimum point.
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
1 Attachment
3.7K
-
In line 7 I'm not sure how f(x min,y min) can be little/equal to c if for all (x,y) f(x,y)>=g((x^2+y^2)^0.5) and g>c?
-
Nevermind. I got it
-
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 973 views
- $10.00
Related Questions
-
Find a general solution for the lengths of the sides of the rectangular parallelepiped with the
largest volume that can be inscribed in the following ellipsoid - Select the Correct Curve Sketches and Equations of Curves
- Integrate $\int_0^1\int_{\sqrt{x}}^{1}e^{y^3}dydx$
- Multivariate Calculus Problem
- Show that $\int_\Omega \Delta f g = \int_\Omega f \Delta g$ for appropriate boundary conditions on $f$ or $g$
- Compute the surface integral $ \int_S (∇ × F) \cdot dS $ for $F = (x − y, x + y, ze^{xy})$ on the given surface
- Compute $\iint_D \frac{dx dy}{\sqrt{1+x+2y}}$ on $D=[0,1]\times [0,1]$
- Stoke's Theorem
Is g continuous?
We don't know. Any way its not a given
Got it! No assumption on g!