Find the absolute extrema of $f(x,y) = x^2 - xy + y^2$ on $|x| + |y| \leq 1$.
Hello. I am confused about how to solve the following Lagrange multiplier problem. It involves in inequality in the constraint so I began by finding the extrema within that domain by simply setting the first derivatives of f to 0, and finding that there is an extremum at (0, 0). However, the absolute values in the constraint confuse me when I try to use Lagrange multipliers. Can someone help me?
Find the absolute extrema of $f(x,y) = x^2 - xy + y^2$ on $|x| + |y| \leq 1$.
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
1 Attachment
Kav10
2.1K
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 1340 views
- $9.00
Related Questions
- Maximum gradient of function within a domain
- Exercise 4.33 from Spivak's Calculus on Manifolds.
- Custom Solutions to Stewart Calculus Problems, 9th Edition
- Find the area bounded by the graphs of two functions
- Calculus helped needed asap !!
- Need Upper Bound of an Integral
- Compute the curl of $F=(x^2-\sin (xy), z-cox(y), e^{xy} )$
- 3 Multi-step response questions
