Find the absolute extrema of $f(x,y) = x^2 - xy + y^2$ on $|x| + |y| \leq 1$.
Hello. I am confused about how to solve the following Lagrange multiplier problem. It involves in inequality in the constraint so I began by finding the extrema within that domain by simply setting the first derivatives of f to 0, and finding that there is an extremum at (0, 0). However, the absolute values in the constraint confuse me when I try to use Lagrange multipliers. Can someone help me?
Find the absolute extrema of $f(x,y) = x^2 - xy + y^2$ on $|x| + |y| \leq 1$.
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
1 Attachment
Kav10
2K
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 600 views
- $9.00
Related Questions
- A telephone line hanging between two poles.
- Mechanical principle help (maths)
- highschool class help
-
For the LP attached , suppose at least 8 oz of chocolate
and at least 9 oz of sugar are required (with other
requirements remaining the same). What is the new optimal
z-value? - Explain what the problem means in laymens terms.
- Find the equation of the tangent line through the function f(x)=3x$e^{5x-5} $ at the point on the curve where x=1
- Two persons with the same number of acquaintance in a party
- Find equation of the tangent line using implicit differentiation