Given $|f(x) - f(y)| \leq M|x-y|^2$ , prove that f is constant.
Let f be differentiable on R and suppose that there exists M > 0 such that, for any x, y $\in$ R, $|f(x) - f(y)| \leq M|x-y|^2$. Prove that f is a constant function.
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
1 Attachment
Kav10
1.9K
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 738 views
- $8.00
Related Questions
- Use Green’s theorem to compute $\int_C x^2 ydx − xy^2 dy$ where $C$ is the circle $x^2 + y ^2 = 4$ oriented counter-clockwise.
- Integral of $\arctan x$
- Use the equation to show the maximum, minimum, and minimum in the future.
- Optimization problem
- Finding absolute and relative extrema given an equation.
- Calculus Questions - Domains; Limits; Derivatives; Integrals
- Help
- Find z(x, y), please help me with this calculus question