Let $R$ be an integral domain and $M$ a finitely generated $R$-module. Show that $rank(M/Tor(M))$=$rank(M)$
I only need item b). Full question:
Let $R$ be an integral domain and $M$ a finitely generated $R$-module.
- a) Show that $M/Tor(M)$ is free of torsion. (ALREADY PROVEN) ✓
- b) Show that $rank(M/Tor(M))$=$rank(M)$.
Answer
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Note that "less than" and "largen than" are to be understood as $\leq$ and $\geq$.
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