Find the limit as x-->0 for y = (e^x- 1)/[sin(nx)]
Find the limit as x-> 0 for y = (e^x- 1)/[sin(nx)]
a. Using L’Hopital’s rule
b. Using the series approximation of e^u = 1 + u and sin(u) = u for u << 1
60
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
1 Attachment
649
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 1146 views
- $15.00
Related Questions
- What is the integral of (x^2-8)/(x+3)dx
- Does $\lim_{(x,y)\rightarrow (0,0)}\frac{(x^2-y^2) \cos (x+y)}{x^2+y^2}$ exists?
- Solution to Stewart Calculus
- Find the area bounded by the graphs of two functions
- Derivatives again. Thank you!
- Calculus word problem
- Help formulating sine function
- Evaluate$\int \sqrt{\tan x}dx$