Car accidents and the Poisson distribution 

In a busy highway on the average 5 accidents happen per week. What is the probability that there will be no accidents next week? Assume that the number of accidents has a Poisson distribution.


Let $X$ be the number of accidents per week. Then $X$ has the Poisson distribution 
\[p(x)=\frac{\lambda^{x}e^{-\lambda}}{x!}, x=0,1,2, \dots .\]
Since the average number of accidents happen per week is $5$, $\lambda=5$. Hence 
\[p(x)=\frac{5^{x}e^{-5}}{x!}, x=0,1,2, \dots .\]
The probabality of no accident is
Note that  $0! =1$. 

Erdos Erdos
The answer is accepted.
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