Prove that $tan x +cot x=sec x csc x$
Answer
\[\tan x + \cot x=\frac{\sin x}{\cos x}+\frac{\cos x}{\sin x}=\frac{\sin ^2 x+\cos^2 x}{\sin x \cos x}\]
\[=\frac{1}{\sin x \cos x}=\frac{1}{\cos x} \cdot \frac{1}{\sin x}\]
\[=\sec x \csc x.\]
\[=\frac{1}{\sin x \cos x}=\frac{1}{\cos x} \cdot \frac{1}{\sin x}\]
\[=\sec x \csc x.\]
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