Prove that $tan x +cot x=sec x csc x$
Answer
\[\tan x + \cot x=\frac{\sin x}{\cos x}+\frac{\cos x}{\sin x}=\frac{\sin ^2 x+\cos^2 x}{\sin x \cos x}\]
\[=\frac{1}{\sin x \cos x}=\frac{1}{\cos x} \cdot \frac{1}{\sin x}\]
\[=\sec x \csc x.\]
\[=\frac{1}{\sin x \cos x}=\frac{1}{\cos x} \cdot \frac{1}{\sin x}\]
\[=\sec x \csc x.\]
Erdos
4.8K
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 3183 views
- $2.00
Related Questions
- Value Of Investment
- Characterizing the Tangent and Normal Bundles - Submanifolds in Banach Spaces and Their Classifications
- Can enough pizza dough be made to cover the surface of the earth?
- Calculating the derivatative
- Foreign Carnival Systems Algebra Problem
- Prove that $1+\frac{1}{\sqrt{2}}+\dots+\frac{1}{\sqrt{n}} \leq 2 \sqrt{n}-1$
- Find $\int x \sqrt{1-x}dx$
- Find the average value of the function $\frac{\sin x}{1+\cos^2 x}$ on the interval $[0,1]$
