Lim x-> +0 ((e^(-1/x))/xª))
1 Answer
The limit is zero for any value of $a$ as the exponetial functions decays faster than any polynomial.
Savionf
574
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So I wouldn't get an indeterminate form of 0/0 ? Thank you in advance
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The limit is of type 0/0, but it converges to zero for any value of a.
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Oh okay and this is because the 0 of x is insignificant compared to the 0 of the exponential ?
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Yes, e^{-1/x} decays faster than any polynomial.
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