Lim x-> +0 ((e^(-1/x))/xª)) 

I need to know what this limit approaches as "a" varies

1 Answer

The limit is zero for any value of $a$ as the exponetial functions decays faster than any polynomial. 

  • Gubiv Gubiv

    So I wouldn't get an indeterminate form of 0/0 ? Thank you in advance

    • Savionf Savionf

      The limit is of type 0/0, but it converges to zero for any value of a.

  • Gubiv Gubiv

    Oh okay and this is because the 0 of x is insignificant compared to the 0 of the exponential ?

    • Yes, e^{-1/x} decays faster than any polynomial.

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