# Advanced Polynomial & Rational Functions

The monthly revenue,R(x),for a big tech company depends on the monthly advertising expenses, x, by the function 𝑅(𝑥) = 1020𝑥/25 + 8x , where the monthly revenue and advertising expenses are in thousands of dollars. (a) What should be the monthly advertising expenses if the company wants the monthly revenue (in dollars ) to exceed $200 000? Include an interval chart in your solution.

## 1 Answer

Note that

\[𝑅(𝑥) = \frac{1020 x}{25} + 8x=40.8x+8x=48.8 x\]

a) If the company wants the monthly revenue (in dollars ) to exceed 200 000 dollars, then we should have

\[𝑅(𝑥) = 48.8 x \geq 200 \Rightarrow x \geq \frac{200}{48.8}=4.098.\]

So the monthly advertising expenses should be at least $4.098 k=4,098$ dollars. So the monthly advertising expenses should be a number in the interval $(4,098, \infty).$

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Could you clarify what you mean by "the monthly revenue and advertising expenses are in 25+8𝑥 thousands of dollars."

made a mistake, its supposed to be R(x) = 1020x/25 + 8x

You question is not clear. Please check your question carefully and revise it.

Could you please revise your question?

i fixed it