# Advanced Polynomial & Rational Functions

The monthly revenue,R(x),for a big tech company depends on the monthly advertising expenses, x, by the function 𝑅(𝑥) = 1020𝑥/25 + 8x , where the monthly revenue and advertising expenses are in thousands of dollars. (a) What should be the monthly advertising expenses if the company wants the monthly revenue (in dollars ) to  exceed  $200 000? Include an interval chart in your solution. • Could you clarify what you mean by "the monthly revenue and advertising expenses are in 25+8𝑥 thousands of dollars." • Mina 0 made a mistake, its supposed to be R(x) = 1020x/25 + 8x • You question is not clear. Please check your question carefully and revise it. • Could you please revise your question? • Mina +1 i fixed it ## 1 Answer Note that $𝑅(𝑥) = \frac{1020 x}{25} + 8x=40.8x+8x=48.8 x$ a) If the company wants the monthly revenue (in dollars ) to exceed 200 000 dollars, then we should have $𝑅(𝑥) = 48.8 x \geq 200 \Rightarrow x \geq \frac{200}{48.8}=4.098.$ So the monthly advertising expenses should be at least$4.098 k=4,098$dollars. So the monthly advertising expenses should be a number in the interval$(4,098, \infty).\$

• Let me know if you have any questions.

• I do have a feeling that you still have a mistake in the formula for R(x).

• Are you sure it is not something like: 𝑅(𝑥) = 1020/25x + 8x ? Double check carefully.

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