Center of mass with triple integral
Calculate the center of mass between $x^2+y^2+z^2=2y$ and $x^2+y^2+z^2=4y$ using a triple integral. The formula for density is given by $f(x,y,z) = (x^2+y^2+z^2)^{1/2}$.
Please show work
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
2 Attachments
Erdos
4.8K
-
There was a small mistake in the solution. Please see the corrected solution (second file).
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 831 views
- $24.60
Related Questions
- Volume of solid of revolution
- I need help with the attched problem about definite integrals
- Evaluate $\frac{1}{2 \pi i}\int_{|x|=1} \frac{z^{11}}{12z^{12}-4z^9+2z^6-4z^3+1}dz$
- Stokes' theorem $\int_S \nabla \times F \cdot dS= \int_C F\cdot dr$ verification
- Need help with integrals (Urgent!)
- Show that the line integral $ \oint_C y z d x + x z d y + x y d z$ is zero along any closed contour C .
- Find the average of $f(x)=\sin x$ on $[0, \pi]$.
- Integration headache, please help.
