Center of mass with triple integral
Calculate the center of mass between $x^2+y^2+z^2=2y$ and $x^2+y^2+z^2=4y$ using a triple integral. The formula for density is given by $f(x,y,z) = (x^2+y^2+z^2)^{1/2}$.
Please show work
Answer
Answers can only be viewed under the following conditions:
- The questioner was satisfied with and accepted the answer, or
- The answer was evaluated as being 100% correct by the judge.
2 Attachments
4.8K
-
There was a small mistake in the solution. Please see the corrected solution (second file).
The answer is accepted.
Join Matchmaticians Affiliate Marketing
Program to earn up to a 50% commission on every question that your affiliated users ask or answer.
- answered
- 1554 views
- $24.60
Related Questions
- Integrate $\int x^2\sin^{-1}\left ( \frac{\sqrt{a^2-x^2} }{b} \right ) dx$
- Find $\int x \sqrt{1-x}dx$
- Evaluate $\iint_{R}e^{-x-y}dx dxy$
- Find the average of $f(x)=\sin x$ on $[0, \pi]$.
- Evaluate $\int \sqrt{\tan x} dx$
- Calculate the antiderivative of trigonometric functions
- Need help with integrals (Urgent!)
- Evaluate $\frac{1}{2 \pi i}\int_{|x|=1} \frac{z^{11}}{12z^{12}-4z^9+2z^6-4z^3+1}dz$