# Solve $abc=2(a-2)(b-2)(c-2)$ where $a,b $ and $c$ are integers

So we must have $$(a-2)(b-2)(c-2)=\frac{abc}{2} \Rightarrow \ \ 2(a−2)(b−2)(c−2)= abc $$

But I don't know how to solve this equation for $a,b$ and $c$.

Erica89

16

## Answer

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Erdos

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The answer is accepted.

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