Fermat's method of calculus
I've attached my question as a file and here is the resource I was looking at https://cedar.wwu.edu/cgi/viewcontent.cgi?article=1012&context=wwu_honors
-
what is the question?
-
you are asking why does this actually work even after answering the same. But you are also sayng you wont get anywhere
-
Your question is very vague. Please clarify.
-
my question basically is why does this method work to give you a tangent line? specifically the steps where you divide by e and then plug 0 in for e
Answer
- The questioner was satisfied and accepted the answer, or
- The answer was disputed, but the judge evaluated it as 100% correct.
-
can you explain further the last part you wrote?
-
In essence, this procedure allows to find the x-axis cross value as a limit operation. When we replace T(x+epsilon) by f(x+epsilon) we are thinking of a sufficiently small epsilon for this to make sense. This is a limit operation t that is quite literally based on Taylor first order approximation.
-
I added another explanation.
- answered
- 153 views
- $6.50
Related Questions
- Find all functions $f: \mathbb{Z} \rightarrow \mathbb{Z}$ such that $f(2n)+2f(2m)=f(f(n+m))$, $\forall m,n\in \mathbb{Z}$
- Studying the graph of this function
- Beginner Differential Equations - Growth Rate Question
- Evaluate the integral $\int_{-\infty}^{+\infty}e^{-x^2}dx$
- Use Rouche’s Theorem to show that all roots of $z ^6 + (1 + i)z + 1 = 0$ lines inside the annulus $ \frac{1}{2} \leq |z| \leq \frac{5}{4}$
- Fourier series
- Calculus - functions, limits, parabolas
- Taylor Polynom/Lagrange form om the remainder term.