Absolute value functions.
How would you go about solving this absolute value inequality? I'll show my attempt to solve them and then hopefully you can tell me where I am going wrong.
$\left | 2x-1 \right |≤ \left | 3x \right |$
So next I would find the different cases.
$2x-1<0 $ or $x<\frac{1}{2} $ case 1
$2x-1≥0$ or $x≥\frac{1}{2} $ case 2
and then solve
$2x-1≤3x$ = $-1≤x$
or
$2x-1≤3x=-x≤1=x≤-1$
My first problem arises here I'm not sure which way I am supposed to solve it, because one way I get x ≤-1 and another way I get -1≤x. What am I doing wrong here? The next problem arises which case do I check to make sure both conditions are right for instance do I do
Now if I try and solve case two I have the same problems.
$2x-1≥-3x = 5x≥1 = x ≥\frac{1}{5} $
or
$2x-1≥-3x=-1≥-5x=\frac{1}{5} ≥x$
Now again I have the same problem where I have two values for x and again which case do a check to see if both conditions are met. This is the problem I am struggling with and I am not sure what I am doing wrong.
Answer
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I understand the logic behind the first way of solving it, but the second way I'm a little unsure when it comes to the intervals I believe they're called. since the bounty was only $10 I don't expect you to do an in-depth explanation of them but if I open up another question on the website and set the bounty to $20 will you be able to answer my further questions? What time will you be online? I really like your way of explaining and I don't want someone else taking the bounty.
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OK, in a couple of hours when I get home, I should be able to provide more explanation on selecting the intervals. You can pay me here, by adding $20 or more tip. Sound good?
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Added detailed steps. With these steps, you should hopefully be all set. When tipping, please remember 20% is taken by the website. Thanks.
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