$I need help with this Trig formula$

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A camera is mounted on a tripod 4 feet high at a distance of 10 feet from Frank, who is 6' tall. If the camera lens has angles of depression and elevation of 20 degrees, will Frank's feet and head be seen by the lens? If not, how far back will the camera need to be moved to include Frank's feet and head?

I can't figure out the formula to this.

Trigonometry Word Problem

Chelsrenee

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The section seen by the camera is centred at 4' and the width is given by (twice, because it goes in both directions) the distance times the tangent of the angle. In your case, that would be $10 \cdot \tan(20°) \sim 3.6$ feet, which is not enough to see Frank's feet (but enough to see Frank's head).

In order to get there, you need to put it at a distance $d$ such that $d \cdot \tan(20°) = 4$, so $d = \frac{4}{\tan{20°}} \sim 11$ feet.

Alessandro Iraci

$I need help with this Trig formula$

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