Composition of three functions
1 Answer
We have
\[y = 3x - 2=y = 3(3t + 2) - 2=9t+6-2=9t+4\]
\[=9(3k - 2)+4=27k-18+4=27k-14.\]
So
\[y=27k-14=f(k).\]
\[y = 3x - 2=y = 3(3t + 2) - 2=9t+6-2=9t+4\]
\[=9(3k - 2)+4=27k-18+4=27k-14.\]
So
\[y=27k-14=f(k).\]
Erdos
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