$a \log_bx=\log_{b^\frac{1}{a}}x$

Is this a valid property of logarithms? Using other exponential and logarithmics laws can you explain why or why not


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Erdos Erdos
  • I think this is my fault. I meant to write the base alone is raised to the power of 1/a, not log_b in the second equation.

    • Erdos Erdos

      Yes! I revised my solution. The statement is true. Let me know if you need any clarifications.

    • Thank you Erdos that explains it perfectly

  • I edited the title accordingly.

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