Show that the MLE for  $\sum_{i=1}^{n}\left(\ln{2x_i} - 2\ln{\lambda} - \left(\frac{x_i}{\lambda}\right)^2\right)$ is $\hat{\lambda} = \sqrt{\sum_{i=1}^{n}\frac{x_i^2}{n}}$.

Firstly, as my assignment is due in 2 hours, I am offering $30. The due time for this post is set to 1 hour only - for the sake of speed, feel free to use pen/pencil on pape

Hi, I have solved the previous question (b), which was:

Consider the function $f(x) = \frac{2x}{\lambda^2}e^{-(\frac{x}{\lambda})^2}$.

Given a dataset consisting of $n$ observations, $x_1, x_2, ..., x_n$, demonstrate that the log-likelihood function is $\sum_{i=1}^{n}\left(\ln{2x_i} - 2\ln{\lambda} - \left(\frac{x_i}{\lambda}\right)^2\right)$.

My solution to (b) is attached as a screenshot.

Now, for (c), they want me to find the MLE for the summation expression from (b) - it is the question I have put in the title of this post.

Please show clear workings and do not skip any steps - this is for a graded college assignment. Thank you.

Calculus Probability Distribution
Angmingwen Angmingwen
65
Matchmaticians Show that the MLE for  $\sum_{i=1}^{n}\left(\ln{2x_i} - 2\ln{\lambda} - \left(\frac{x_i}{\lambda}\right)^2\right)$ is $\hat{\lambda} = \sqrt{\sum_{i=1}^{n}\frac{x_i^2}{n}}$. File #1 File #1 (png)
Matchmaticians Show that the MLE for  $\sum_{i=1}^{n}\left(\ln{2x_i} - 2\ln{\lambda} - \left(\frac{x_i}{\lambda}\right)^2\right)$ is $\hat{\lambda} = \sqrt{\sum_{i=1}^{n}\frac{x_i^2}{n}}$. File #2 File #2 (png)
Matchmaticians Show that the MLE for  $\sum_{i=1}^{n}\left(\ln{2x_i} - 2\ln{\lambda} - \left(\frac{x_i}{\lambda}\right)^2\right)$ is $\hat{\lambda} = \sqrt{\sum_{i=1}^{n}\frac{x_i^2}{n}}$. File #3 File #3 (png)
Report
  • Mathe Mathe
    0

    I can't find the screenshot.

    • Angmingwen Angmingwen
      0

      Sorry Mathe. Just attached it.

    • Angmingwen Angmingwen
      0

      That was my working for the previous question.

    • Angmingwen Angmingwen
      0

      The screenshot lacks one piece of context - the function $f(x)$ is given in the question. It is not included in the screenshot.

    • Angmingwen Angmingwen
      0

      I added a second file. This file contains the entire question and all its subquestions. I solved (1), and (2), and I asked for (3) on this platform.

  • Angmingwen Angmingwen
    0

    MLE being Maximum Likelihood Estimator.

  • Angmingwen Angmingwen
    0

    Please let me know if you need anything else - also, my hard deadline for the assignment is exactly in 2.5 hours, so, if you need more time, I will extend to 2 hours. However, the earlier obviously the better for me, so I have more time to understand and transfer it onto Latex.

  • Angmingwen Angmingwen
    0

    The 3rd file is an example of MLE being used to find the probability of a coin getting heads when flipped 3 times. Only problem is, I don't know how to apply the same concept\differentiation to a sum.

    • Mathe Mathe
      0

      One takes derivative with respect to the parameter one wants to estimate, in this case, lambda. We can ignore any term that doesn't have any lambda, and treat any x_i observation as a constant.

  • Angmingwen Angmingwen
    0

    Yeah sure I understand that!

Answer

Answers can only be viewed under the following conditions:
  1. The questioner was satisfied with and accepted the answer, or
  2. The answer was evaluated as being 100% correct by the judge.
View the answer

1 Attachment

Mathe Mathe
3.5K
  • Angmingwen Angmingwen
    0

    Sorry Mathe, I must say I'm a bit confused - I don't follow the first 3 lines. Where does 2n*ln(lambda) come from in the 2nd line? How did a summation operator in the last expression on the 2nd line? Why are there 2 summation operators on the 3rd line?

  • Angmingwen Angmingwen
    0

    I hope you provide more explanation. This isn't just for you to solve, but also for me to understand ~ I will need to transfer it into my own work.

    • Mathe Mathe
      0

      I'll be more explicit next time!

  • Angmingwen Angmingwen
    +1

    Nevermind, its quite basic. Thanks, I will accept it now.

The answer is accepted.
Join Matchmaticians Affiliate Marketing Program to earn up to a 50% commission on every question that your affiliated users ask or answer.