# Doubt about Vector Spaces A∩B

Hello, in my university exam, I came across the following problem:

Find the basis of A∩B for A=lin{ a1, a2, a3} and B=lin{b1, b2, b3}.

My question is, if I prove that: b1, b2 ∈ A, is it undeniably certain that A∩B=lin{b1, b2}?

I demonstrated in the specific case of my exam (where there were indeed numbers) that b3 is linearly independent from a1, a2, and a3, while b1 and b2 are linearly dependent on a1 and a2.

If I prove that: $b_1, b_2 \in A$, is it undeniably certain that $A\cap B=lin\{b_1, b_2\}$?

The answer is NO.  You can simply take $A=B=\{i,j,k\}$. Then $A\cap B=\{i,j,k\}.$

In general, it is posisble to also  $b_3 \in A$, and if $b_3$ is linearly independent from $b_1$ and $b_2$, then
$$b_3 \in lin\{b_1, b_2,b_2\} \text{but} b_3 \notin lin\{b_1, b_2\}.$$
So $A\cap B \neq lin\{b_1, b_2\}.$

However, if $b_3$ is not linearly independent of $b_1$ and  $b_2$, then $A\cap B=lin\{b_1, b_2\}$ is true.

Join Matchmaticians Affiliate Marketing Program to earn up to 50% commission on every question your affiliated users ask or answer.